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The angle of minimum deviation produced ...

The angle of minimum deviation produced by a `60^(@)` prism is `40^(@)`. Calculate the refractive index of the material of the prism.

A

`1.512`

B

`1.522`

C

`1.532`

D

`1.632`

Text Solution

Verified by Experts

The correct Answer is:
C
`A = 60^(@) , delta_(m) = 40^(@)`
`n = (sin (A + (delta_(m))/(2)))/(sin ((A)/(2))) = (sin ((60^(@) + 40^(@))/(2)))/(sin ((60^(@))/(2)))`
`(sin 50^(@))/(sin 30^(@)) = (0.766)/(1//2) = 1.532`
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