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The refractive angle of a prism is 60^(@...

The refractive angle of a prism is `60^(@)` . What is the angle of minimum deviation, if the refractive index of the material of the prism is `sqrt2` ?

A

`30^(@)`

B

`35^(@)`

C

`40^(@)`

D

`20^(@)`

Text Solution

Verified by Experts

The correct Answer is:
A

`n = ( sin ((A + delta_(m))/(2)))/(sin ((A)/(2)))`
` sqrt2 = (sin ((60^(@) + delta_(m))/(2)))/(sin ((60^(@))/(2)))`
But `sin 30^(@) = (1)/(2)`
`therefore sin ((60^(@) + delta_(m))/(2)) = sqrt2 xx (1)/(2) = (1)/(sqrt2) = sin 45^(@)`
`therefore (60^(@) + delta_(m))/(2) = 45^(@)`
`therefore 60^(@) + delta_(m) = 90^(@) therefore delta_(m) = 30^(@)`
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