When an equilateral prism is placed in the position of minimum deviation , the incident ray makes an angle of `37^(@)` with the refracting surface . What is the material of the prism , if the angle of `37^(@)` with the refracting surface . What is the angle of minimum deviation ?

Options

A. `42^(@)`
B. `44^(@)`
C. `46^(@)`
D. `48^(@)`

Answer

C

Explanation

The incident ray makes an angle of `37^(@)` with the refracting surface .
`therefore i= 90^(@) - 37^(@) = 53^(@)` and when the ray suffers minimum deviation , `i= e = 53^(@)`
`therefore` Using `i+ e = A + delta_(m) ` , we get
`delta_(m) = 53^(@) + 53^(@) - 60^(@) = 46^(@)`