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A luminous point object is placed at a d...

A luminous point object is placed at a distance of 20 cm, from the pole of a convex spherical surface of glass. The radius of the curvature of the convex surface is 25 cm and the R.I. of the glass is 1.5. What is the distance of the image from its pole ?

A

v=20 cm in glass

B

v=30 in glass

C

v=30 cm in air

D

v=40 cm in glass

Text Solution

Verified by Experts

The correct Answer is:
B
`u=-20 cm, R=5 cm, n_(1)=1, n_(2)=1.5`
`therefore (n_(2))/(v)-(n_(1))/(u)=(n_(2)-n_(1))/(R )`
`therefore (1.5)/(v)-(1)/((-20))=(1.5-1)/(5)=(1)/(10)`
`therefore (1.5)/(v)=(1)/(10)-(1)/(20)=(1)/(20)`
`therefore v=20xx1.5=30 cm`
`therefore` The image is formed at a distance of 30 cm form the pole, in glass.
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