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The magnetic moment of a circular curren...

The magnetic moment of a circular current loop is `2.3 xx10^(-5) Am^(2)`. What is the magnitude of the magnetic field on the axis of the loop at a distance of 1 cm from the loop?

A

`2.6xx10^(-6) T`

B

`3.6xx10^(-6) T`

C

`4.6xx10^(-6) T`

D

`5.6xx10^(-6) T`

Text Solution

Verified by Experts

The correct Answer is:
C
The loop acts as a short magnetic dipole
`:. B_("axis")=mu_(0)/(4pi) (2M)/d^(3)=(10^(-7) xx2xx2.3xx10^(-5))/((10^(-2))^(3))`
`=4.6xx10^(-6) T` or `"Wb/m"^(2)`
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