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What is the magnetic induction due to a short magnetic dipole of moment `0.1 Am^(2)` at an equatorial point 10 cm away from the centre of the dipole/

A

`10^(-4)" Wb/m"^(2)`

B

`10^(-5)" Wb/m"^(2)`

C

`10^(-6)" Wb/m"^(2)`

D

`2xx10^(-5)" Wb/m"^(2)`

Text Solution

Verified by Experts

The correct Answer is:
B
`B_("equator")=mu_(0)/(4pi) M/d^(3)`
`=10^(-7)xx0.1/((10^(-1))^(3))=10^(-5)" Wb/m"^(2)`
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