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Calculate the magnetic field due to a ba...

Calculate the magnetic field due to a bar magnet `2cm` long and having pole strength of `100A-m` at a point `10cm` from each pole.

A

`2xx10^(-5) T`

B

`8pixx10^(-4) T`

C

`4xx10^(-4) T`

D

`2xx10^(-4) T`

Text Solution

Verified by Experts

The correct Answer is:
D

The point lies on the equator of the bar magnet.
`:. B=mu_(0)/(4pi) M/((d^(2)+l^(2))^(3//2))`
`M=mxx2l=100xx2xx10^(-2) =2`
`(d^(2)+l^(2))^(1//2)=sqrt((100+1)xx10^(-4))`
`div 10 xx10^(-2) =10^(-1)`
`:. B=10^(-7)xx2/((10^(-1))^(3))=2xx10^(-4) T`
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