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What is the dimensions of magnetic field...

What is the dimensions of magnetic field B in term of C( coulomb), M, L and T ?

A

`MT^(-2) C^(-1)`

B

`MLT^(-1) C^(-1)`

C

`MT^(2)C^(-2)`

D

`MT^(-1) C^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
D
`vec(F)=q(vec(v)xxvec(B))` or `F=qv B sin theta`
`:. B=F/(qv)` (`sin theta` has no dimensions)
`:. [B]=([M^(1)L^(1)T^(-2)])/([C][L^(1)T^(-2)])=[M^(1)T^(-1) C^(-1)]`
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