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A bar magnet of magnetic moment 0.4 Am^(...

A bar magnet of magnetic moment `0.4 Am^(2)` is placed in a uniform magnetic field of induction `5 xx10^(-2)` tesla. The angle between the magnetic induction and the magnetic moment is `30^(@)`. The torque acting on the magnet is

A

0.5 Nm

B

`10^(-1)` Nm

C

`10^(-2)` Nm

D

`10^(-3)` Nm

Text Solution

Verified by Experts

The correct Answer is:
C
`tau =MB sin theta=0.4xx5xx10^(-2) xx1/2=10^(-2) N-m`
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