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A bar magnet of pole strnegth 2A-m is ke...

A bar magnet of pole strnegth `2A-m` is kept in a magnetic field of induction `4xx10^(-5)wbm^(-2)` such that the axis of the magnet makes an angle `30^(@)` with the directon of the field. The couple acting on the magnet is found `80xx10^(-7)N-m`. Then the distance between the poles of the magnet is

A

8 m

B

2 m

C

4 m

D

20 cm

Text Solution

Verified by Experts

The correct Answer is:
D
`tau =MB sin theta`
`tau=(mxx2l) B sin theta`
`:. 2l=tau/(mB sin theta)=(80xx10^(-7))/(2xx4xx10^(-5) xx sin 30^(@))`
`=2xx10^(1)=0.2 m=20 cm`
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