Home
Class 11
PHYSICS
At a certain place, the horizontal compo...

At a certain place, the horizontal component of earth's magnetic field is `sqrt(3)` times the vertical component. The angle of dip at that place is

A

`30^(@)`

B

`45^(@)`

C

`60^(@)`

D

`75^(@)`

Text Solution

Verified by Experts

The correct Answer is:
C

`tan delta=B_(V)/B_(H)` ...(1)
and `B_(V)/B_(H)=sqrt(3)` ...(2)
`:. tan delta =sqrt(3) :. Delta =60^(@)`
Promotional Banner

Topper's Solved these Questions

  • MAGNETISM

    MARVEL PUBLICATION|Exercise TEST YOUR GRASP|10 Videos
  • MAGNETIC EFFECT OF ELECTRIC CURRENT

    MARVEL PUBLICATION|Exercise TEST YOUR GRASP|10 Videos
  • MEASUREMENTS

    MARVEL PUBLICATION|Exercise TEST YOUR GRASP|10 Videos

Similar Questions

Explore conceptually related problems

At a certain place , the horizontal component of earth's magnetic field is (1)/(sqrt3) times of its vertical component . The angle of dip at that place is

The horizontal component of earth’s magnetic field at a place is sqrt""3 times the vertical component. The angle of dip at that place is

The horizontal component of earth's magnetic field is sqrt3 times the vertical component . What is the value of angle of dip at this place ?

At a certain place , horizontal component of earth's field is sqrt3 times the vertical component of earth's field . The angle of dip at this place is

Horizontal component of earth’s magnetic field at a place is sqrt()3 times the vertical component. What is the value of inclination at that place?

The vertical component of earth's magnetic field at a place is sqrt3 times the horizontal component the value of angle of dip at this place is