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The equation of displacement of a harmon...

The equation of displacement of a harmonic oscillator is x =`3sin omega t`+4 `cos omega t`amplitude is

A

2

B

5

C

7

D

12

Text Solution

Verified by Experts

The correct Answer is:
B
`x=3 "sin"g omega t +4 "cos" omega t " " therefore A = sqrt(3^(2)+4^(2))=5`
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