A particle performs a linear S.H.M. of period 3 second. The time taken by the particle to cover a dis"tan"ce equal to half the amplitude, from the mean position is

Options

A. `1//2` second
B. `1//4` second
C. `3//4` second
D. 1 second

Answer

B

Explanation

`x=(A)/(2)=A "sin" ((2pi t)/(T))`
`therefore (1)/(2)="sin" (pi)/(6)= "sin" ((2pi t)/(T))`
`therefore (2pi t)/(3)=(pi)/(6) therefore t=(1)/(4)=0.25 s`