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A particle executes a linear S.H.M. of a...

A particle executes a linear S.H.M. of amplitude A and period T. It starts from the mean position. The time required to cover a dis"tan"ce A/2 is

A

`(T)/(4)`

B

`(T)/(3)`

C

`(T)/(8)`

D

`(T)/(12)`

Text Solution

Verified by Experts

The correct Answer is:
D
`(A)/(2)=A "sin" ((2pi t)/(T))`
`therefore (1)/(2)="sin" (pi)/(6)= "sin" (2pi t)/(T) therefore t=(T)/(12)`
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