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The displacement at an ins"tan"t t, of a...

The displacement at an ins"tan"t t, of a particle executing a linear S.H.M. is given by x=5 "sin" 31.4(t+0.1). Its periodic time is

A

2 sec

B

0.2 sec

C

0.5 sec

D

1 sec

Text Solution

Verified by Experts

The correct Answer is:
B
`x= 5 "sin" 31.4 (t + 0.1)=5 "sin" [31.4 t+3.14]` comparing with `x=A "sin" ((2pi t)/(T)+alpha) " we get " (2pi)/(T)=31.4`
`therefore T=(2xx3.14)/(31.4)=0.2 s`
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