The amplitude of oscillation of a particle executing a linear S.H.M. is `(5)/(pi^(2))` cm, If its frequency is 20 Hz, then the magnitude of its maximum acceleration will be

Options

A. `20 m//s^(2)`
B. `40 m//s^(2)`
C. `80 m//s^(2)`
D. `100 m//s^(2)`

Answer

C

Explanation

Maximum acceleration `=omega^(2)A=4pi^(2)n^(2)A`
`=4 xxpi^(2)xx400xx(5)/(pi^(2))xx10^(-2)=80 m//s^(2)`