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The acceleration of a particle performin...

The acceleration of a particle performing a S.H.M. is `0.12 m//s^(2)`, when the particle is at a dis"tan"ce of 3 cm from its equilibrium position. What is the period of S.H.M. ?

A

3.14 s

B

6.28 s

C

1.57 s

D

10 s

Text Solution

Verified by Experts

The correct Answer is:
A
`T=2pi sqrt((x)/(a))=2xx3.14sqrt((3xx10^(-2))/(12xx10^(-2)))=3.14 s`
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