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The maximum velocity of a linear simple ...

The maximum velocity of a linear simple harmonic oscillator represented by `y=6 "sin" (50 t +pi//3)` is given by [all quantities are in SI units]

A

100 m/s

B

300 m/s

C

`6 pi m//s`

D

`pi//3 m//s`

Text Solution

Verified by Experts

The correct Answer is:
B
`y= a "sin" (omega t+ alpha) and y=6 "sin" (50 t+(pi)/(3))`
`therefore omega =50`
`therefore " Maximum velocity " = omega A=50xx6=300 m//s`
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