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The maximum velocity of a particle perfo...

The maximum velocity of a particle performing a linear S.H.M. of amplitude 1.4 cm is `4.4 m//s`. What is the period of S.H.M. ?

A

0.1 s

B

0.2 s

C

2 s

D

0.02 s

Text Solution

Verified by Experts

The correct Answer is:
D
Maximum velocity `=omega A=(2pi)/(T)A`
`therefore 4.4 =(pi)/(T)xx1.4xx10^(-2)`
`therefore T=(2xx1.4xx10^(-2))/(4.4)xx(22)/(7)=2xx10^(-2)=0.02 s`
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