A particle is executing a simple harmonic motion. Its maximum acceleration is `alpha` and maximum velocity is `beta`. Then, its time period of vibration will be

Options

A. `T=(2 pi beta)/(alpha)`
B. `T=(2 pi alpha)/(beta)`
C. `T=(beta)/(2pi alpha)`
D. `T=(alpha)/(2pi beta)`

Answer

B

Explanation

`(beta)/(alpha)=("Max. acceleration")/("Max. velocity")=(A omega^(2))/(A omega)=omega =(2pi)/(T)`
`therefore T=(2pi alpha)/(beta)`