A block rests on a horizontal table which is executing SHM in the horizontal plane with an amplitude A. What will be the frequency of oscillation, the block will just start to slip? Coefficient of friction`=mu`.

Options

A. `2pisqrt((A)/(mu g))`
B. `(1)/(2pi)sqrt((mu g)/(A))`
C. `(2pi mu g)/(A)`
D. `(1)/(4pi)sqrt((mu g)/(A))`

Answer

B

Explanation

`m omega^(2)A= mu mg therefore omega =sqrt((mu g)/(A))=2 pi n`
`therefore n =(1)/(2pi)sqrt((mu g)/(A))`