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A particle is performing a linear S.H.M....

A particle is performing a linear S.H.M. If at time t=0, its displacement is 1 cm, its velocity is `pi cm//sec` and its angular frequency is `pi rad//s`, then the amplitude of its motions is

A

1 cm

B

`sqrt(2) cm`

C

3 cm

D

`pi cm`

Text Solution

Verified by Experts

The correct Answer is:
B
`v=omegasqrt(A^(2)-x^(2)) therefore pi = pi sqrt(A^(2)-1^(2))`
`therefore 1 = A^(2)-1 therefore A=sqrt(2) cm`
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