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The maximum velocity a particle, executi...

The maximum velocity a particle, executing simple harmonic motion with an amplitude 7 mm, 4.4 m//s. The period of oscillation is.

A

0.1 s

B

100 s

C

0.01 s

D

10 s

Text Solution

Verified by Experts

The correct Answer is:
A
`V_("max")=omega A=(2piA)/(T)`
`therefore T= (2piA)/(V_("max"))=(2xx22xx7xx10^(-3))/(7xx4.4)`
`therefore T= 10^(-2) s=0.01 s`
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