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A particle is executing a linear S.H.M. ...

A particle is executing a linear S.H.M. and its differential equation is `(d^(2)x)/(dt^(2))+ alpha x=0`. Its time period of motion is

A

`(2 pi)/(alpha)`

B

`2 pi alpha`

C

`2pi sqrt(alpha)`

D

`(2pi)/(sqrt(alpha))`

Text Solution

Verified by Experts

The correct Answer is:
D
`T=(2pi)/(omega)=(2pi)/(sqrt(alpha))`
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