A small wooden cube is placed on a plank. The plank performs a vertical S.H.M. of frequency `(3)/(pi) Hz`. What is the maximum amplitude of its vertical S.H.M., so that the wooden cube does not leave the plank ?` [g=10 m//s^(2)]`

Options

A. `(5)/(12)m`
B. `(5)/(18)m`
C. `(7)/(12)m`
D. `(11)/(18)m`

Answer

B

Explanation

The wooden cube also performs a S.H.M. of amplitude A. The wooden cube does not leave th plank.
For this `mAomega^(2)`=weight (mg)
`therefore A=(g)/(omega^(2))=(g)/(4pi^(2)n^(2))=(10)/(4pi^(2)xx(9)/(pi^(2)))=(5)/(18)m`