The displacement of a particle performing a S.H.M. is given by `x =12 "cos" (omega t + alpha) cm`. If at time t, the displacement of the particle is 6 cm, them the phase of the particle at that instant is

Options

A. `(pi)/(6)` radian
B. `(pi)/(4)` radian
C. `pi` radian
D. `(pi)/(3)` radian

Answer

D

Explanation

`x=12 "cos" (omega t+ alpha) therefore (6)/(12) = "cos" (pi)/(3) = "cos" (omega t+ alpha)`
`therefore " Phase " (omega t+ alpha)=(pi)/(3)`