Two particles A and B execute simple harmonic motions of period T and `5T//4`. They start from mean position. The phase difference between them when the particle A complete an oscillation will be

Options

A. `(pi)/(5)` rad
B. `(2pi)/(5)` rad
C. `(pi)/(2)` rad
D. `(pi)/(3)` rad

Answer

B

Explanation

Phase difference `=(omega_(1)-omega_(2)) t =((2pi)/(T)-(2pi)/(5T//4))t`
`=(2pi)/(T)(1-(4)/(5))=(2pi t)/(5T)`
For one complete oscillation t= T
`therefore` Phase difference `=(2pi)/(5)` radian