The force constant of a linear harmonic oscillator is 10 N/m. If is P.E. at a point in its path is 0.05J, its corresponding displacement is

Options

A. 1 metre
B. 0.5 m
C. 0.25 m
D. 0.1 m

Answer

D

Explanation

P.E. `=(1)/(2) kx^(2)`
`therefore (5)/(100)=(1)/(2)xx10xx x^(2) therefore x=0.1 m`