For a particle performing a S.H.M. the potential and kinetic energies will be equal when the displacement of the particle is

Options

A. A
B. `(A)/(2)`
C. `A sqrt(2)`
D. `(A)/(sqrt(2))`

Answer

D

Explanation

`(1)/(2)m omega^(2)x^(2)=(1)/(2)m omega^(2)(A^(2)-x^(2))`
`therefore x^(2)=A^(2)-x^(2) therefore x=(A)/(sqrt(2))`