When the displacment in S.H.M. is half the amplitude, the ratio of potential energy to the total energy is

Options

A. `(1)/(2)`
B. `(1)/(8)`
C. 1
D. `(1)/(4)`

Answer

D

Explanation

`(P.E.)/("Total energy")=((1)/(2)m omega^(2) (A^(2))/(4))/((1)/(2)m omega^(2) A^(2))=(1)/(4)`