A simple harmonic oscillator has a period T and energy E. the amplitude of the oscillator is doubled. Choose the correct answer.

Options

A. the period gets houbled while energy remains the same
B. the period remains the same and energy becomes for times
C. both the period and the energy get doubled
D. energy gets doubled while the period remains the same

Answer

B

Explanation

`E=(1)/(2)m omega^(2)A^(2)=(1)/(2)m (4pi^(2))/(T^(2))A^(2)=(2pi^(2)mA^(2))/(T^(2))`
`E prop A^(2)`
`therefore` When A is doubled, E becomes four times while T remains the same. T does not depend upon A.