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A simple pendulum, suspended from the co...

A simple pendulum, suspended from the coiling of a lift, has a period of oscillation T, when the lift is at rest. If the lift starts moving upwards with an acceleration a =3g, then the new period will be

A

2T

B

4T

C

`(T)/(3)`

D

`(T)/(2)`

Text Solution

Verified by Experts

The correct Answer is:
D
New acceleration =g +a=4g
`therefore T_(2)=2pi sqrt((l)/(4g))=(1)/(2) [2pi sqrt((l)/(g))]=(1)/(2)T_(1)`
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