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The bob of a pendulum of length l is pul...

The bob of a pendulum of length l is pulled aside from its equilibrium position through an angle `theta` and then released. The bob will then pass through its equilibrium position with a speed v, where v equals

A

`sqrt(2gl)`

B

`sqrt(2gl(1+ "cos" theta))`

C

`sqrt(2gl(1-"cos" theta))`

D

`sqrt(2gl(1+"sin" theta))`

Text Solution

Verified by Experts

The correct Answer is:
C

`(1)/(2) mv^(2)=mgh=mgl (1-"cos" theta)`
`therefore v=sqrt(2gl (1-"cos" theta))`
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