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The acceleration due to gravity at a pla...

The acceleration due to gravity at a place changes from `9.8 m//s^(2) " to " 9.5 m//s^(2)`. Then the length of the second's pendulum changes by

A

0.3 m

B

3 cm

C

0.3 cm

D

6 cm

Text Solution

Verified by Experts

The correct Answer is:
B

`T=2pi sqrt((L)/(g)) therefore 4=(4pi^(2)L)/(g) therefore L=(g)/(pi^(2))`
`therefore L_(1)-L_(2)=(g_(1)-g_(2))/(pi^(2))=0.03m= 3cm`
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