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A simple pendulum executing S.H.M. is fa...

A simple pendulum executing S.H.M. is falling freely along with the support. Then

A

its periodic time increases

B

its periodic time decreases

C

its periodic time does not change

D

it des not oscillate at all

Text Solution

Verified by Experts

The correct Answer is:
D

For a freely falling body g=0.
`therefore T=2pi sqrt((l)/(g)) to oo therefore` It does not oscillate.
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