The length of a simple pendulum is increased by 1%. Its time period will

Options

A. increase by 2%
B. decrease by 2 %
C. increase by 0.5 %
D. decrease by 0.5 %

Answer

C

Explanation

`T prop sqrt(l)`
`(T_(2))/(T_(1))=sqrt((1.01 l)/(l))=(1+(1)/(100))^(1//2) =(1+(1)/(2xx100))`
`therefore` percentage increase in period
`=((T_(2)-T_(1))/(T_(1)))xx100=(1)/(200)xx100=0.5%`