The periodic time of a simple pendulum is 6.28 sec and the amplitude of oscillation is 3 cm. The maximum acceleration of the pendulum is

Options

A. `5 cm//s^(2)`
B. `4 cm//s^(2)`
C. `3 cm//s^(2)`
D. `2 cm//s^(2)`

Answer

C

Explanation

For small angular displacements, the bob of a simple pendulum performs a S.H.M. so that maximum acceleration `=omega^(2)A=(4pi^(2))/(T^(2))xxA`
But `T=6.28 s=2xx(3.14)s=2p s and T^(2)=4pi^(2)`
`therefore a_("max")=(4pi^(2))/(4pi^(2))xx3 =3 cm//s^(2)`