A simple pendulum suspended from the ceiling of a trans has a time period `T` when the train is at rest. If the train is accelerating uniformly at `a` then its time period

Options

A. Decrease
B. Remain unaffected
C. Become infinite
D. Increase

Answer

A

Explanation

When the train is at rest, `T_(1)=2pi sqrt((l)/(g))`
But when the train accelerates, the resul"tan"t acceleration will be `sqrt(g^(2)+a^(2))`
and `T_(2)=2pi sqrt((l)/(g^(2)+a^(2)) because T_(2) lt T_(1)`
i.e. T is decreased.