A particle executes a linear S.H.M. of amplitude A and period T. It starts from the mean position. The time required to cover a dis"tan"ce A/2 is

Options

A. `(T)/(6)`
B. `(T)/(12)`
C. `(T)/(3)`
D. `(T)/(4)`

Answer

A

Explanation

`x= A "cos" omega t`
`therefore (A)/(2)=A "cos" ((2pi t)/(T)) therefore (1)/(2)= "cos" (pi)/(3)= "cos" ((2pi t)/(T))`
`therefore (pi)/(3)=(2pi t)/(T) therefore t =(T)/(6)`