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When a spring is compressed by 0.05 m a ...

When a spring is compressed by 0.05 m a restoring force of 10 N is developed in it. Then the force constant of the spring is

A

50 N/m

B

100 N/m

C

150 N/m

D

200 N/m

Text Solution

Verified by Experts

The correct Answer is:
D

`K=(F)/(x)=(10)/(5xx10^(-2))=2xx10^(2)=200 N//m`
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