A mass M attached to a spring oscillates with a period of 1s. If the mass is increased by 3 kg the period increases by 1s. What is the value of M, assuming that Hooke's law is obeyed ?

Options

A. 3 kg
B. 2 kg
C. 1 kg
D. 5 kg

Answer

C

Explanation

`T_(1)=2pi sqrt((M)/(K)) and T_(2)=2pi sqrt((M+3)/(K))`
`therefore (T_(2))/(T_(1))=2= sqrt((M+3)/(M)) therefore 4 = (M+3)/(M)`
`therefore 4M =M +3 therefore 1 kg`