A mass is suspended from a spring having spring constant k is displaced veritcally and relased. It oscillates with period T the weight of the mass suspended is (g= gravitatioanal acceleration)

Options

A. `(KT g)/(4pi^(2))`
B. `(KT^(2)g)/(4 pi^(2))`
C. `(KT g)/(2pi^(2))`
D. `(KT^(2)g)/(2pi^(2))`

Answer

B

Explanation

For the spring `T=2pi sqrt((m)/(K))`
`therefore T^(2)=(4pi^(2)m)/(K) therefore m=(T^(2)K)/(4pi^(2))`
`therefore` Weight of the mass `=mg = (T^(2)Kg)/(4pi^(2))`