A flat spiral spring of force constant K is loaded with mass M and oscillates vertically with a time period T. Then the mass suspended to the free end is

Options

A. `(4pi^(2))/(KT^(2))`
B. `(KT^(2))/(4pi^(2))`
C. `(KT)/(4pi^(2))`
D. `(KT)/(4pi)`

Answer

B

Explanation

For the spring, `T=2pi sqrt((m)/(K))`
`therefore T^(2)=(4pi^(2)m)/(K) therefore m=(T^(2)K)/(4pi^(2))`