A spring of force constant k is cut into two pieces such that one piece is double the length of the other. Then the long piece will have a force constant of:

Options

A. 2K
B. 3K
C. `(3)/(2)K`
D. `(2)/(3)K`

Answer

C

Explanation

If L is the length of the spring, then the lengths of the two pieces will be `(2L)/(3) and (L)/(3)`. IF `K_(1)` is the spring constant of the longer piece, then
`(K_(1))/(K)=(L)/(2L//3)=3 therefore K_(1)=(3)/(2) K`