Figure shows the displacement time graphs of two simple harmonic motions I and II. From the graph it follows that

Options

A. curve I has same frequency as that of curve II
B. curve I has a frequency twice that of curve II
C. curve I has a frequency half that of cure II
D. curve I has frequency four times that of curve II

Answer

C

Explanation

For the first curve, one oscillation is completed in 8 s.
Period `T_(1)=8s`
`therefore " Frequency " n_(1)=(1)/(T_(1))=(1)/(8) Hz`
For the second curve, one oscillation is completed in 4s.
`therefore "Period " T_(2)=4s " and frequency " n_(2)=(1)/(T_(2))=(1)/(4)Hz`
`therefore (n_(1))/(n_(2))=(1//8)/(1//4)=(1)/(2) or n_(1)=(1)/(2)n_(2)`
Thus (c ) is the correct option.