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A particle executing SHM. The phase diff...

A particle executing SHM. The phase difference between acceleration and displacement is

A

`(pi)/(2)` rad

B

`pi rad`

C

`2pi rad`

D

`(3pi)/(2) rad`

Text Solution

Verified by Experts

The correct Answer is:
B
`x=A "sin" omega t and a= - omega^(2) A "sin" omega t = - omega^(2)x`
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