We draw the reference circle of a particle (M) performing a linear S.H.M. If the period of M is 2 sec, then the angular velocity of the reference particle will be

Options

A. `2pi` radian/sec
B. `(pi)/(2)` radian/sec
C. `pi` radian/sec
D. `(3pi)/(2)` radian/sec

Answer

C

Explanation

The period of the S.H.M. particle moving along the diameter = the period of the particle moving along the reference circle =2s
`therefore` Its angular velocity `=(2pi)/(T)=(2pi)/(2)=pi rad//s`