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A particle is executing a linear S.H.M. ...

A particle is executing a linear S.H.M. Its velocity at a dis"tan"ce x from the mean position is given by
`v^(2)=144-9x^(2)`. [x is in metre]
What is the amplitude of S.H.M. ?

A

2m

B

4m

C

3m

D

5m

Text Solution

Verified by Experts

The correct Answer is:
B
The velocity in S.H.M. is `v^(2)=omega^(2)(A^(2)-x^(2))` and it is given that `v^(2)=144-9x^(2)=9(16-x^(2))`
Comparing these two expressions, we get
`omega^(2)=9 and A^(2)=16 therefore A=4 m`
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