The displacement of a particle performing S.H.M. is given by `x=10 "sin"(omega t+ alpha)` metre. If the displacement of the particle is 5m, then the phase of S.H.M. is

Options

A. `(pi)/(3)` radian
B. `(pi)/(6)` radian
C. `(pi)/(4)` radian
D. `(pi)/(2)` radian

Answer

B

Explanation

`x=5=10 "sin" (omega t+alpha)`
`therefore (1)/(2)= "sin" (pi)/(6) = "sin" (omega t+ alpha)`
`therefore` Phase `=(omega t+alpha)=(pi)/(6)`