The phase of a particle performing a linear S.H.M. increases by `(pi)/(4)` after every 5 sec. What is the frequency of its oscillation ?

Options

A. `(1)/(10)Hz`
B. `(1)/(20)Hz`
C. `(1)/(30) Hz`
D. `(1)/(40)Hz`

Answer

D

Explanation

In a linear S.H.M. , the phase increases by `2pi` in period T.
For a phase change of `(pi)/(4)`, time t=5s
`therefore` For a phase change of `2pi`, time T=8t =40s
`therefore` Frequency of oscillation `=(1)/(40)Hz`